- nmacholl
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Member for 12 years, 6 months, and 2 days
Last active Sun, Aug, 5 2012 11:56:40
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Oct 22, 2011nmacholl posted a message on Diablo III Open Q&AHas anyone found a picture of the program with the lady-Diablo?Posted in: News
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e: really bliz should make it so that the stack meets the $1 transaction fee. So as long as you're selling enough of the commodity to make more than a dollar off the stack they should allow it. Or have a percentage based fee.
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Yeah I was a little concerned about having to stand still for Ray of Frost. Though I never really have a problem landing comet. So far in Hell I've been having good luck using frost nova to freeze enemies and then blasting them with two comets.
This seems to be the paradigm though I do really like mirror images.
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Cheers.
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I'm sure Inferno has an achievement, and achievements have unlock dates. It is tracked in the game, just not tracked globally across the player base. Honestly your world would be no different if you never saw this thread.
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So you're not going to be playing multiplayer at all then?
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This is the best way to farm gear.
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I'm sure there will be plenty of viable inferno groups that don't use the MMO paradigm.
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Competitive gaming appeals to people. Look how many 'speed runs' of classic Nintendo games exist on YouTube. If a group of players wants to be competitive about Diablo 3 let them, you're not being forced to participate or even acknowledge their existence.
I personally welcome it because it helps build the community around a game I hope to play for years.
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Keep in mind that the probability of a dog not respawning is 1 - .35 or .65; so we multiply as always.
This answer is correct, but not complete. There are FOUR different ways only one dog could respawn and just like calcualting probability of throwing two dice (or four in this case) we need to sum up the probabilties of each permutation.
Since our 'dice rolls' are identical each time we can just multiply the above result by 4 to get the correct anwser of 38.4%
The reason I didn't need to do this for 'all dogs' or 'no dogs' is becauase there is only one permutation for those cases.
Isn't math great?
Edit: I think this is easier to do mentally than using binomial formulas; but this is the basic machinery behind those functions.
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For instance, a single die has a 1/6th (1 in 6) chance of coming up a 3 when you roll it. To figure out the probability of rolling two threes, just multiply 1/6th by 1/6th which is 1/36.
With a 35% chance of resurrecting, if all dogs die at the same time, the calculation for getting four resurrections in a row is .35 multiplied by itself 4 times.
For none resurrecting, we're interested in the chances of a resurrection NOT happening. The chances of that are 1 - .35 or .65 (65%).
The in betweens are a combination of the two methods and I'll let you figure those out.
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