Pretty basic question... assuming you have a graphing calculator... I'd just use that for everything but the first part... (local min/max function and you can just search the table of every point for the one when Y=0 for when the ball lands) - still use the calculator but... just to check work for the parts that want you to find the max by formula... not sure what math you are in, but the max will be a point in which the slop is equal to zero.. first derivative is the slope.. so take the derivative and set it equal to zero and solve for T. so you get... -32t+64=0 > -32t=-64 > t=2 .. second derivative is -32 < 0 making it a local max (not certain on this part)...
just plug in 2 for t and solve for H
to graph the original function - just plug in points... and solve for T or H...
if this is wrong, you must forgive me, been like 4 years since I took or used calc1 or 2...
for F and G - just solve the function for when H=0 and when h=250...
I'm going to assume this means sketching a rough picture, as putting in numbers on a TI-84 or equivalent calculator seems a bit redundant for a question.
If you have to sketch, just select some numbers, preferably points where the x and y-axis are crossed (is that a correct term? Don't usually do this in English). You should also realize from the equation that this is a parabola, which will tell you how the rough figure will look.
Quote from name="Lt Venom" »
Find the maximum height of the projectile using formulas and calculation.
You could use the derivative here and find where the value is 0, and since this is a quadratic equation, only one result will be returned. That will be the correct one.
Quote from name="Lt Venom" »
c) Find the maximum height of the projectile from the graph.
Umm, look at the graph? If it's on the calculator and you use some TI model, it's under Calc -> maximum. Select two points on each side of the maximum and let the calculator do the rest.
The height is obviously graphed on the y-axis, so that's the value you'll be looking at for this question.
Quote from name="Lt Venom" »
d) Compare your answers from part a, b and explain any discrepancies.
Well, this question would mean you are in fact supposed to draw the graph. Any difference would probably be because the drawing won't be exact, while the equation is.
Quote from name="Lt Venom" »
e) From the graph find the time t when the projectile reaches its maximum height.
t is the x-axis in this case, so just see what value t has when the graph reaches its maximum.
Quote from name="Lt Venom" »
f) Find the time when the projectile hits the ground (height of 0 feet).
This is when the h(t) = 0. There are two points like these, but obviously the point which has a positive value for t is the one we're looking for. The other one is not a real value, as it describes when the projectile would have been fired from the ground.
Insert h(t) = 0 into the function and solve with pq for t. (Is it called pq in english as well? I can't recall).
Quote from name="Lt Venom" »
g) Find the time(s) that the projectile reaches the height of 250 feet.
Insert into the equation and calculate using the pq-formula. Since the projective is fired from 100 feet, you will get two positive results. One one the way up for the projective, one when it comes down again. Both values for t are thus correct.
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PlugY for Diablo II allows you to reset skills and stats, transfer items between characters in singleplayer, obtain all ladder runewords and do all Uberquests while offline. It is the only way to do all of the above. Please use it.
Supporting big shoulderpads and flashy armor since 2004.
My god you all in calculus are somethin? I couldent understand a word of math any of you said
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If you want to arrange it
This world you can change it
If we could somehow make this
Christmas thing last
By helping a neighbor
Or even a stranger
And to know who needs help
You need only just ask
I was taught this in 9th grade algebra... are you sure your teacher is not just reviewing you over algebra?
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It's 3am. rain. thunder, lightning. silence. silence. thunder. wind, howling wind. pricks of sound the rain makes. slowly. as it trickles down your roof. behold the solemn nature. behold the beauty of the storm.
I'm currently in 10th grade taking Geometry, and I should be taking that class right now, but last year there was not enough room in the current class I'm in.
Wait, nevermind, I just re-read the problem. Learned it two years ago in Algebra.
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It's the decisions you make when you have no time to make them that define who you are.
1: The height of a projectile with an initial velocity of 64 ft/sec and an initial height of 100 ft. is given by
h(t)= -16t squared + 64t + 100
a) Graph the function.
Find the maximum height of the projectile using formulas and calculation.
c) Find the maximum height of the projectile from the graph.
d) Compare your answers from part a, b and explain any discrepancies.
e) From the graph find the time t when the projectile reaches its maximum height.
f) Find the time when the projectile hits the ground (height of 0 feet).
g) Find the time(s) that the projectile reaches the height of 250 feet.
just plug in 2 for t and solve for H
to graph the original function - just plug in points... and solve for T or H...
if this is wrong, you must forgive me, been like 4 years since I took or used calc1 or 2...
for F and G - just solve the function for when H=0 and when h=250...
h(t) = -16t^2 + 64t +100
I'm going to assume this means sketching a rough picture, as putting in numbers on a TI-84 or equivalent calculator seems a bit redundant for a question.
If you have to sketch, just select some numbers, preferably points where the x and y-axis are crossed (is that a correct term? Don't usually do this in English). You should also realize from the equation that this is a parabola, which will tell you how the rough figure will look.
You could use the derivative here and find where the value is 0, and since this is a quadratic equation, only one result will be returned. That will be the correct one.
Umm, look at the graph? If it's on the calculator and you use some TI model, it's under Calc -> maximum. Select two points on each side of the maximum and let the calculator do the rest.
The height is obviously graphed on the y-axis, so that's the value you'll be looking at for this question.
Well, this question would mean you are in fact supposed to draw the graph. Any difference would probably be because the drawing won't be exact, while the equation is.
t is the x-axis in this case, so just see what value t has when the graph reaches its maximum.
This is when the h(t) = 0. There are two points like these, but obviously the point which has a positive value for t is the one we're looking for. The other one is not a real value, as it describes when the projectile would have been fired from the ground.
Insert h(t) = 0 into the function and solve with pq for t. (Is it called pq in english as well? I can't recall).
Insert into the equation and calculate using the pq-formula. Since the projective is fired from 100 feet, you will get two positive results. One one the way up for the projective, one when it comes down again. Both values for t are thus correct.
Do you want actual calculations as well?
So, glad I could be of help I suppose
If you want to arrange it
This world you can change it
If we could somehow make this
Christmas thing last
By helping a neighbor
Or even a stranger
And to know who needs help
You need only just ask
Weaseling out of things is important to learn. It's what separates us from the animals... except the weasel.
- Homer Simpson
rain.
thunder, lightning.
silence.
silence.
thunder.
wind, howling wind.
pricks of sound the rain makes.
slowly.
as it trickles down your roof.
behold the solemn nature.
behold the beauty of the storm.
I'm currently in 10th grade taking Geometry, and I should be taking that class right now, but last year there was not enough room in the current class I'm in.
Wait, nevermind, I just re-read the problem. Learned it two years ago in Algebra.
It's the decisions you make when you have no time to make them that define who you are.
I always remember people being so squemish about manually graphing stuff.
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